Week 5 Problem set - CONDENSED KEY

1. a) the time required for the compound to pass through the column

b) increase

c) decrease

d) decrease

2. Cyclopentanol is more polar than cyclopentanone. Thus the cyclopentanol would spend more time in the stationary phase.

3. Yes. The retention time for cyclopentanol would decrease and for cyclopentanone it would increase.

4. Polarity is not an issue here since diethyl ether has a significantly lower boiling point than borneol.

5. The compounds need time to interact with the stationary phase. If they pass through the column too fast (because of too high of a flow rate) or if the column temp is too high (so that the compounds always stay in the gas phase) then the compounds will never interact with the stationary phase.