SUMMER 1999
MIDTERM II
, 14C
ANSWER KEY
MOUSER, July 22

1.

a. 3-methylbutanal
b. 1-(4-ethoxyphenyl)-1-propanone

1-ethoxy-4-(1-propanoyl)benzene or (4-ethoxyphenyl) ethyl ketone

c. 3-methyl-2-cyclohexenecarbaldehyde
d. (Z)-2-methyl-2-butenal

if cis -2 pts

e. 1-ethyl-3-cyclopentenecarboxylic acid(R)-2-cyclohexen-1-ol
f. HO—CH2CH2CH2CO2H
g. CH3C(O)CH2CH2CH2CO2H

2. 80°C, 98°C, 36°C
3. 8, 2, 5
4. 3, 3
3, 7
5. for deuterium I = 1; Multiplicity = 2nI+1 = 2 x 2 x 1 + 1 = 5 peaks, quintet
6.

thus, the conjugate base of acetone is more stable than the conjugate base of ethane.

7.

a stronger acid and a stronger base on the reactant's side of the equation favors the forward direction (or reaction to the right).

8. B is considerably more acidic; the conjugate base of B is more stable. The cyclopentatrienyl anion is not aromatic. The cyclopentadienyl anion is aromatic. (Show structures for full credit).

9.

10.

Dilute sample: A sharp O—H signal is expected under dilute conditions. (Hydrogen bonding with another alcohol is unlikely under dilute conditions either because of spatial separation (gas phase) or solvent separation.)

Neat sample: A broad O—H signal is expected resulting from hydrogen bonding between molecules. However, due to the nearby bulky tert-butyl groups, hydrogen bonding interactions between molecules is sterically encumbered.

11. water, 16; amine 38; ketone 19-20; alcohol 16-19; ketone 19-20; alkyne 25

12. C5H9BrO; Exact Mass: 163.9837

13. a. 134 peak

b.

c. 91 peak

d.

14. B, E, D, G

15.

IR Spectrum:

A, =C—H stretch

B, C—H stretch

C, aromatic overtones

D, C=C alkene stretch

E, C=C aromatic stretch

F, C—O stretch

Proton NMR:

A & B, Aromatic

C, O—CH2—CH=CH2

D, O— CH2—CH=CH2

E, O— CH2—CH=CH2

Carbon NMR:

A, ipso aryl carbon

B, O—CH2CH=CH2

C, O—CH2—CH=CH2

D, O—CH2—CH=CH2

16.

17.