1) heavier; having the extracting solvent as the bottom layer in a separatory funnel minimizes the number of transfers.
0.10w0 = w0 (v1 / ((K (v2/n) +v1))n
Since v1 = v2/n and K = 0.5; assign v1 = 1 unit volume
0.10 w0 = w0 (1 / ((0.5 (1) +1))n = w0 (0.666)n
thus,
0.10 w0 = w0 (0.666)n
0.10 = (0.666)n
n = 5.6
6 extractions is needed.
thus,
amounted extracted into phase two = w0 - w0 (v1 / ((K (v2/n) +v1))n
substituting V1 into V2 we get,
= w0 - w0 (v1 / ((K (v2/n) +v1))n
= w0 - w0 (0.5)n
if n = 1,
= w0 - w0 (0.5)1 = 0.50 w0 or 50%
if n = 2,
= w0 - w0 (0.5)2 = 0.70 w0 or 75%
if n = 3,
= w0 - w0 (0.5)2 = 0.875 w0 or 87.5%
if n = 4,
= w0 - w0 (0.5)2 = 0.9375 w0 or 94%
11) Add NaCl (salting out).