Spectrum 1: 9-Cyanophenanthrene (solid)

Frequency Assignment
3072-3020 n(CH, sp2)
2220 n(C=N)
1611, 1526 n(C=C, aromatic)
745, 719 oop bending, monosubst.

Spectrum 2: Dodecanol (solid)

Frequency Assignment
3411, 3349 n(OH, alcohol, diol)
2924, 2850 n(CH, sp3)
1461 d (CH3, bend)
1364, 1350 d (CH3, CH2, bend)
1058, 1041 n(C-OH)

Spectrum 3: Endo-5-norbornene-2,3-dicarboxylic anhydride (solid)

Frequency Assignment
3012, 3034 n(CH, sp2)
2982, 2956, 2880 n(CH, sp3)
1854, 1773 n(C=O, stretch, anhydride)
1231, 1090 n(COC)

Spectrum 4: 4,4'-isopropylidenediphenol (bisphenol A, solid)

Frequency Assignment
3348 n(OH, alcohol)
~3020 n(CH, sp2)
2966 n(CH, sp3)
1612, 1599, 1508 n(C=C, aromatic)
1447 d (CH3, bend)
1364 d (CH3, CH2, bend)
1239 n(C-OH)
827 oop, para-substituted

Spectrum 5: 1,5-Cyclooctadienone (liquid)

Frequency Assignment
3370 n(C=O, overtone)
2864-2942 n(CH, sp3)
1690 n(C=O, stretch)
1329 d (CH2, bend)

Spectrum 6: Dimethoxybutane (liquid)

Frequency Assignment
2964, 2930, 2868 n(CH, sp3)
1450 d (CH3, bend)
1376 d (CH3, CH2, bend)
1056, 827 n(COC, ether)

Spectrum 7: 1-Chloro-3-Nitro-benzylalcohol (solid)

Frequency Assignment
3400-2800 n(OH, alcohol)
2847, 2963 n(CH2, sp3)
1606, 1500 n(C=C, aromatic)
1519, 1340 n(NO2)
1037 n(C-OH)
749 n(CCl)

Spectrum 8: 1,3,5-Tribenzenetricarboxylic acid (solid)

Frequency Assignment
3500-2500 n(OH, acid)
1719 n (C=O)
1607 n(C=C, aromatic)

Spectrum 9: 1,1-Diphenylethylene (liquid)

Frequency Assignment
3080, 3056, 3029 n(CH, sp2)
1610, 1495 n(C=C, aromatic)
898 oop, 1,1-disubst. alkene
698, 773 oop, mono-subst. ring

Spectrum 10: Diethyl phenylmalonate (liquid)

Frequency Assignment
3454 n(C=O, overtone)
3065 n(CH, sp2)
2980, 2935, 2874 n(CH, sp3)
1737 n (C=O)
1603, 1499 n(C=C, aromatic)
1180, 1031 n(C-O, ester)
1455, 1369 d (CH2, CH3, bend)


General comments:

1. The average grade for the assignment is 36 points (out of 40). If you scored significantly less than 30 points, I would advise you to see your TA or the instructor to seek some help.

2. One of the most common mistakes was not to analyze the
n(C-H) region correctly to determine what type of compound (alkane, alkene, aromatic, or mixed) is present.

3. The
n(OH) peaks for acids and alcohols look very different and can be easily identified by looking at them (see reader). However, in some cases intramolecular hydrogen bonding broadens and shifts (to lower wavenumbers) the peak of an alcohol.

4. Carbonyl peaks can be shifted to lower wavenumbers when the carbonyl function is conjugated to another
p-system e.g. double bond or aromatic ring.

5. Nitro groups show two intense peaks in the IR spectrum: one between 1300-1400 cm-1 for the symmetric stretching mode, the other one between 1500-1600 cm-1 for the asymmetric stretching mode.

6. The presence of two peaks in the carbonyl range (1630-1850 cm-1) indicates either the presence of an "anhydride type" of function or two different carbonyl functions.

7. Peaks due to amine, alkyne or alcohol functions are very different in appearance. Alkyne peaks (CH stretch) are very sharp and fairly intense due to an "isolated" motion. Amine peaks are usually a little broader and less intense. The presence of two peaks suggests a primary amine (NH2) while secondary amines show only one peak in this range. Alcohols (OH-stretch) usually show a rounded peak in this area.

8. A lot of noise of the left side of the spectrum usually indicates that the spectrum was acquired as a KBr pellet, often times indicating that the compound is a solid.